The Range Of The Function F(K) = K2 + 2k + 1 Is {25, 64}. What Is The Function’S Domain?

The Range Of The Function F(K) = K2 + 2K + 1 Is {25, 64}. What Is The Function’s Domain?. Then the domain of f (k) are all possible values of k such. ← prev question next question →.

The set {25, 64} this means that the function is bounded. When k = 5, k² + 2k + 1 = 36. We know that for polynomial functions like its domain and its rank are all real numbers.

However, For This Case We Are Told That The Function Range Is:

X 2 + 2x + 1 = 25. What is the functions domain? Range = {25, 64} to find the domain of the given function.

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The range of the function f (k) = k² + 2k + 1 is {25, 64}. The set {25, 64} this means that the function is bounded. Ie k² + 2k + 1 can only take two values 25 or 64.

Asked Feb 27 In Calculus.

In this case, we substitute 25 and 64 to y. We know that for polynomial functions like its domain and its rank are all real numbers. Best answer #1 +33191 +5 1.

Consider For K = X Range Is 25.

Set f (k) = 64 k 2 + 2k + 1 = 64 k. What is the function’s domain? What is the function’s domain?

When K = 8, K² +.

However, for this case we are told that the function range is: When k = 5, k² + 2k + 1 = 36. Then the domain of f (k) are all possible values of k such.