Let F(X) = 3x - 6 And G(X) = X - 2. Find F(G(5)) - Ie. (F O G)(5) And Its Domain
Let F(X) = 3X - 6 And G(X) = X - 2. Find F(G(5)) - Ie. (F O G)(5) And Its Domain. You can solve this in two ways: Domain of the fraction is set of all real numbers except 2.
We have variables in the denominator. F (g(x)) f ( g ( x)) evaluate f (6x2) f ( 6 x 2) by substituting in the value of g g into f f. F (g(x)) f ( g ( x)) evaluate f (x+ 2) f ( x + 2) by substituting in the value of g g into f f.
Effective Tutor Specializing In Math And Computer Science About This Tutor › F (X) = X/6 G (X) = 3X/2 (F + G) (X) = X/6 + 3X/2 Now Get A Common Denominator = X/6 + 9X/6 = 10X/6 =.
So an inverse function when composed with the original function is the identity function. Set the denominator = 0. Domain of the fraction is set of all real numbers except 2.
The Identity Function Takes X To X.
Set up the composite result function. At 2 the given fraction will be. F (2x2) = 3(2x2)+ 6 f ( 2 x 2) = 3 ( 2 x 2) + 6 multiply 2 2 by 3 3.
Functions Are F (X) = 3X + 2 G (X) = 7X + 6 We Have To Find F.
You'll get a detailed solution from a subject matter expert that helps you learn core concepts. F (g(x)) f ( g ( x)) evaluate f (x+ 2) f ( x + 2) by substituting in the value of g g into f f. F (x) + g(x) = ( − 3x − 6) +(5x + 2) first, remove the terms from parenthesis being careful to manage the signs of the individual terms correctly:
F (6X2) = 3(6X2)+ 5 F ( 6 X 2) = 3 ( 6 X 2) + 5 Multiply 6 6 By 3 3.
F (x) + g(x) =. We have variables in the denominator. Set up the composite result function.
Plugging The 4 Into G(X) And Then Putting What You Get From That In To F (X) (2).
Because x can be any real number. Solving for x in f (f (x)) = g(f (x)) where f (x) = 3x, g(x) = x2 −3. Example 16 let f(x) = x2and g(x) = 2x + 1 be two real functions.
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