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Given The Geometric Sequence Where A1 = 4 And The Common Ratio Is 3, What Is The Domain For N?

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Given The Geometric Sequence Where A1 = 4 And The Common Ratio Is 3, What Is The Domain For N?. When there is a common ratio ( r) between consecutive terms, we can say this is a geometric sequence. Remember, domain is input, and.

Calculate a5 for the geometric sequence in which a1=1600 and the common
Calculate a5 for the geometric sequence in which a1=1600 and the common from brainly.com

We are asked to find the domain for n. Hence a2 = 2 × 3(2−1) = 2 ×31 = 2 ×3 =. So we need to know what our is.

Divide Each Term By The Previous Term To Determine Whether A Common Ratio Exists.


Remember, domain is input, and. C) all integers where n ≥ −1. An = a1 ⋅ rn−1 → a1 is the first term, r is the common ratio, n is the term you are trying to find.

First, Let's Write The Geometric Sequences In An Equation Where We Can Plug Them In:


So when we do that we get negative nine divided by three, which. The domain of a sequence is always n is an element of positive integers +z, or in other words, 1, 2, 3, 4,., etc. Given equation is a n=3 n−1.

Substitute N=1,2,3,4 In The Given Equation, W E Get.


A geometric sequence is a sequence of terms (or numbers) where all ratios of every two consecutive terms give the same value (which is called the common ratio). According to statement a1 = 4 and r = 3. When there is a common ratio ( r) between consecutive terms, we can say this is a geometric sequence.

If R Is Greater Than 1 Than It Includes Integers Greater Than.


The geometric sequence where, a1 = a = 5 and the common ratio (r) = −3. Given the geometric sequence where a1 = 2 and the common ratio is 4, what is the domain for n? And the common ratio for a geometric sequence is the second term divided by the first term.

A Geometric Sequence Is A Collection Of Numbers, That Are Related By A Common Ratio.


An = a1rn−1 a3 = − 8 = a1r3−1 ⇒ −8 = a1r2 a6 = 1 = a1r6−1 ⇒ 1 = a1r5 ⇒ 1 = a1r2r3 but −8 = a1r2 ⇒ 1 = − 8r3 ⇒ − 1 8 = r3 ⇒ r = − 1 2 a3 = a1r3−1 ⇒ −8 = a1 ⋅ ( − 1. Now, to find the fifth. D) all integers where n.

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